Problem 4 Solution Sketch


  • f(2) is how high the dot is on the graph when x = 2; it looks about 8 units high.
  • Solving the equation y = f(x) = 2 graphically is done by graphing f(x) and graphing y = 2 , and see when they intersect. They intersect at the approximate values x = -4.25 and x = 0.25.
  • The domain is found by listing all the places where vertical lines would hit the graph; this would happen for all -4 < = ; x < = 10. The range is found by listing all the places where horizontal lines would hit the graph. This would happen for all -4 < = y < = 12.
  • This is found by listing all the x-values where the graph is rising (from left to right). This happens when -5 < x < -4, and when -1 < x < 1.75 (approximately!)
  • This is found by listing all of the x-values where the graph would hold water; this is true for all -2 < x < 10.
  • The graph would look almost the same; the only difference is that the new one would go 3 times as high and 3 times as low (so up to 36 and down to -12), and that it would get to the end(s) twice as fast (so only as far left as -2.5 and as far right as 5.)
  • f(g(-1)) = f(3) (which from the graph is about 7.)
    g(f(-1)) = g(-4) (I read f(-1) = -4 from the graph) = 2(-4) + 5 = -3.
    (g+f)(-1) = g(-1) + f(-1) = 3 + (-4) = -1.

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