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f(2) is how high the dot is on the graph when x = 2; it looks about
8 units high.
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Solving the equation y = f(x) = 2 graphically is done by graphing f(x)
and graphing y = 2 , and see when they intersect. They intersect at the
approximate values x = -4.25 and x = 0.25.
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The domain is found by listing all the places where vertical lines
would hit the graph; this would happen for all -4 < = ; x < = 10. The
range is found by listing all the places where horizontal lines would hit
the graph. This would happen for all -4 < = y < = 12.
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This is found by listing all the x-values where the graph is rising
(from left to right). This happens when -5 < x < -4, and when -1 <
x < 1.75 (approximately!)
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This is found by listing all of the x-values where the graph would
hold water; this is true for all -2 < x < 10.
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The graph would look almost the same; the only difference is that the
new one would go 3 times as high and 3 times as low (so up to 36 and down
to -12), and that it would get to the end(s) twice as fast (so only as far
left as -2.5 and as far right as 5.)
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f(g(-1)) = f(3) (which from the graph is about 7.)
g(f(-1)) = g(-4) (I read f(-1) = -4 from the graph) = 2(-4) + 5 = -3.
(g+f)(-1) = g(-1) + f(-1) = 3 + (-4) = -1.
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